And still you got the math wrong
by
Rrhain
08/13/2007, 5:56 PM #
Two huge, glaring errors in the analysis.
1) Your description of how the group of 10 sexually active women are divvied out to the 100 sexually active men is inaccurate.
If there are 100 women, 90 of whom have never had sex and 10 of whom have had sex, that doesn't mean they've all had the same number of partners. There could be unique pairings of one man and one woman for nine of the women and the tenth woman could then have sex with the remaining 91 men.
Note, this would not change the median or the average, but it would change the standard deviation (and only a little bit of a pun there). It seems you assumed each woman would have an average number of partners. Instead, the number of sexual partners can be distributed any way you want so long as each of the 10 sexually active women have at least one partner.
2) You've equivocated the median and the mode. Yes, the median is the value such that half of the data points are below and half are above. Thus, the median might not exist as an actual data point if there are an even number of data points. In that case, you take the middle point between the two in the middle. That is, if I have $10 and you have $100, the median is $55, an amount neither of us have.
But you brought up the concept of "typical" and that isn't the median. That's the mode. The mode is the most common value in a data set. If there are multiple values that appear just as often, then the group has multiple modes. If we have six people, one with $10, two with $20, and three with $100, then the average is $58.33, the median is $60, but the mode is $100.
Each value is important. But since we know that the average is heavily affected by outliers, we don't rely on that single number to tell us anything. That's where things like standard deviation and variance come in. It lets us know just how varied around the average things are.
The problem with the median is that it doesn't tell you just how much spread there is. If there are three people, one with $49, one with $50, and one with $51, the median is $50. But if those three people have one with $0, one with $50, and one with $100, the median is still $50 and we don't have any way of seeing how varied the population is.
The problem with the mode is that it is simply the most common result. This is the seeming paradox that most people don't have the most common outcome. If we have 101 people, the first 100 of which have that much money ($1 for person 1, $2 for person 2, etc.) and person 101 has $50, then the mode is $50, even though 98% of people don't have the mode.
That's why good studies report mean, median, and mode as well as standard deviation.